Fluffy Fishy Posted March 18, 2016 Share Posted March 18, 2016 Does anyone have much data on the strain on the breeching rope, I saw some information about the 42lb cannons creating a force of about 16 tons and was wondering if people had more information on this topic. Link to comment Share on other sites More sharing options...
Capt. Rice Posted March 18, 2016 Share Posted March 18, 2016 http://forum.game-labs.net/index.php?/topic/2487-realistic-cannon-penetration/ was this what you were looking for? Link to comment Share on other sites More sharing options...
Fluffy Fishy Posted March 18, 2016 Author Share Posted March 18, 2016 There is a lot of information but not what I am looking for, thank you anyway . I am looking specifically for the backward force, you see the ropes holding the cannon in place in the picture, I am looking for some information of how much force they had to stand up to. It was a massive amount, be it for a very short space of time. I am just curious if anyone has looked into it really. Link to comment Share on other sites More sharing options...
Capt. Rice Posted March 18, 2016 Share Posted March 18, 2016 (edited) then the formula for recoil is needed right? Pf+Pp=0 where is the momentum of the cannon and is the momentum of the projectile. In other words, immediately after firing, the momentum of the cannon is equal and opposite to the momentum of the projectile. Edited March 18, 2016 by Capt. Rice 1 Link to comment Share on other sites More sharing options...
Fluffy Fishy Posted March 18, 2016 Author Share Posted March 18, 2016 At the risk of sounding uneducated, I'm sorry but that sounds a bit too much science for me to cope with, are you saying you can work that out from the data on the link you posted? How does the momentum reflect on the backwards force, I get the feeling its more complex than that formula shows, I am out of my depth. Link to comment Share on other sites More sharing options...
Fluffy Fishy Posted March 18, 2016 Author Share Posted March 18, 2016 Would it be something like weight x range = force, and thats what is projected backwards? Link to comment Share on other sites More sharing options...
Young Posted March 18, 2016 Share Posted March 18, 2016 (edited) well for every action there is an equal and opposite reaction. It is just that simple. I think the complexity comes in when you have several forces working on the ropes at the same time. Not only the cannon firing but also the heel of the ship the roughness of the seas and so on. Edited March 18, 2016 by Young 2 Link to comment Share on other sites More sharing options...
KrakkenSmacken Posted March 21, 2016 Share Posted March 21, 2016 (edited) well for every action there is an equal and opposite reaction. It is just that simple. I think the complexity comes in when you have several forces working on the ropes at the same time. Not only the cannon firing but also the heel of the ship the roughness of the seas and so on. Not to mention the drag on the rollers, force delivered to the hull of the ship due to cannon angle, slip and settle travel of the cannon in the frame, the difference in velocity due to weight, gradual application of force on the ropes as pulley slack was taken up, ejected material, (the non-powder plugs and such, and any force channels due to barrel design. (did they do anything like that last one in the design like a recoil-less riffle?) Edited March 21, 2016 by KrakkenSmacken Link to comment Share on other sites More sharing options...
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